1.96=x^2+x

Solution for 1.96=x^2+x equation:

1.96=x^2+x

We move all terms to the left:

1.96-(x^2+x)=0

We get rid of parentheses

-x^2-x+1.96=0

We add all the numbers together, and all the variables

-1x^2-1x+1.96=0

a = -1; b = -1; c = +1.96;
Δ = b2-4ac
Δ = -12-4·(-1)·1.96
Δ = 8.84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{8.84}}{2*-1}=\frac{1-\sqrt{8.84}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{8.84}}{2*-1}=\frac{1+\sqrt{8.84}}{-2}
$